Solve y=3-2x/3+2x

$$y = \frac { 3 - 2 x } { 3 + 2 x }$$

Solve for x

$$x=-\frac{3\left(y-1\right)}{2\left(y+1\right)}$$

$$y\neq -1$$

Steps for Solving Linear Equation

Variable x cannot be equal to -\frac{3}{2} since division by zero is not defined. Multiply both sides of the equation by 2x+3.

$$y\left(2x+3\right)=3-2x$$

Use the distributive property to multiply y by 2x+3.

$$2yx+3y=3-2x$$

Add 2x to both sides.

$$2yx+3y+2x=3$$

Subtract 3y from both sides.

$$2yx+2x=3-3y$$

Combine all terms containing x.

$$\left(2y+2\right)x=3-3y$$

Divide both sides by 2y+2.

$$\frac{\left(2y+2\right)x}{2y+2}=\frac{3-3y}{2y+2}$$

Dividing by 2y+2 undoes the multiplication by 2y+2.

$$x=\frac{3-3y}{2y+2}$$

Divide 3-3y by 2y+2.

$$x=\frac{3\left(1-y\right)}{2\left(y+1\right)}$$

Variable x cannot be equal to -\frac{3}{2}.

$$x=\frac{3\left(1-y\right)}{2\left(y+1\right)}\text{, }x\neq -\frac{3}{2}$$

Solve for y

$$y=-\frac{2x-3}{2x+3}$$

$$x\neq -\frac{3}{2}$$