Solve y=3/3x+4-1

$$y = \frac { 3 } { 3 x + 4 } - 1$$

Solve for x

$$x=-\frac{4y+1}{3\left(y+1\right)}$$

$$y\neq -1$$

Steps for Solving Linear Equation

Variable x cannot be equal to -\frac{4}{3} since division by zero is not defined. Multiply both sides of the equation by 3x+4.

$$y\left(3x+4\right)=3+\left(3x+4\right)\left(-1\right)$$

Use the distributive property to multiply y by 3x+4.

$$3yx+4y=3+\left(3x+4\right)\left(-1\right)$$

Use the distributive property to multiply 3x+4 by -1.

$$3yx+4y=3-3x-4$$

Subtract 4 from 3 to get -1.

$$3yx+4y=-1-3x$$

Add 3x to both sides.

$$3yx+4y+3x=-1$$

Subtract 4y from both sides.

$$3yx+3x=-1-4y$$

Combine all terms containing x.

$$\left(3y+3\right)x=-1-4y$$

The equation is in standard form.

$$\left(3y+3\right)x=-4y-1$$

Divide both sides by 3y+3.

$$\frac{\left(3y+3\right)x}{3y+3}=\frac{-4y-1}{3y+3}$$

Dividing by 3y+3 undoes the multiplication by 3y+3.

$$x=\frac{-4y-1}{3y+3}$$

Divide -1-4y by 3y+3.

$$x=-\frac{4y+1}{3\left(y+1\right)}$$

Variable x cannot be equal to -\frac{4}{3}.

$$x=-\frac{4y+1}{3\left(y+1\right)}\text{, }x\neq -\frac{4}{3}$$

Solve for y

$$y=-\frac{3x+1}{3x+4}$$

$$x\neq -\frac{4}{3}$$