Solve y=3/2x+1

$$y = \frac { 3 } { 2 x + 1 }$$

Solve for x

$$x=-\frac{1}{2}+\frac{3}{2y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to -\frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by 2x+1.

$$y\left(2x+1\right)=3$$

Use the distributive property to multiply y by 2x+1.

$$2yx+y=3$$

Subtract y from both sides.

$$2yx=3-y$$

Divide both sides by 2y.

$$\frac{2yx}{2y}=\frac{3-y}{2y}$$

Dividing by 2y undoes the multiplication by 2y.

$$x=\frac{3-y}{2y}$$

Divide 3-y by 2y.

$$x=-\frac{1}{2}+\frac{3}{2y}$$

Variable x cannot be equal to -\frac{1}{2}.

$$x=-\frac{1}{2}+\frac{3}{2y}\text{, }x\neq -\frac{1}{2}$$

Solve for y

$$y=\frac{3}{2x+1}$$

$$x\neq -\frac{1}{2}$$