Solve for k
k=\frac{2\left(y+3\right)}{3}
Solve for y
y=\frac{3\left(k-2\right)}{2}
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\frac{3}{2}k-3=y
Swap sides so that all variable terms are on the left hand side.
\frac{3}{2}k=y+3
Add 3 to both sides.
\frac{\frac{3}{2}k}{\frac{3}{2}}=\frac{y+3}{\frac{3}{2}}
Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
k=\frac{y+3}{\frac{3}{2}}
Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.
k=\frac{2y}{3}+2
Divide y+3 by \frac{3}{2} by multiplying y+3 by the reciprocal of \frac{3}{2}.
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