Solve y=3+x/4-x

$$y = \frac { 3 + x } { 4 - x }$$

Solve for x

$$x=\frac{4y-3}{y+1}$$

$$y\neq -1$$

Steps for Solving Linear Equation

Variable x cannot be equal to 4 since division by zero is not defined. Multiply both sides of the equation by -x+4.

$$y\left(-x+4\right)=3+x$$

Use the distributive property to multiply y by -x+4.

$$-yx+4y=3+x$$

Subtract x from both sides.

$$-yx+4y-x=3$$

Subtract 4y from both sides.

$$-yx-x=3-4y$$

Combine all terms containing x.

$$\left(-y-1\right)x=3-4y$$

Divide both sides by -y-1.

$$\frac{\left(-y-1\right)x}{-y-1}=\frac{3-4y}{-y-1}$$

Dividing by -y-1 undoes the multiplication by -y-1.

$$x=\frac{3-4y}{-y-1}$$

Divide 3-4y by -y-1.

$$x=-\frac{3-4y}{y+1}$$

Variable x cannot be equal to 4.

$$x=-\frac{3-4y}{y+1}\text{, }x\neq 4$$

Solve for y

$$y=\frac{x+3}{4-x}$$

$$x\neq 4$$