Solve for x_3
x_{3}=\frac{8\left(y-4\right)}{27}
Solve for y
y=\frac{27x_{3}}{8}+4
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\frac{27x_{3}}{8}+4=y
Swap sides so that all variable terms are on the left hand side.
\frac{27x_{3}}{8}=y-4
Subtract 4 from both sides.
27x_{3}=8y-32
Multiply both sides of the equation by 8.
\frac{27x_{3}}{27}=\frac{8y-32}{27}
Divide both sides by 27.
x_{3}=\frac{8y-32}{27}
Dividing by 27 undoes the multiplication by 27.
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