Solve y=2x/sqrt{3}+n

$$y = \frac { 2 x } { \sqrt { 3 } } + n$$

Solve for x

$$x=-\frac{\sqrt{3}\left(n-y\right)}{2}$$

Steps for Solving Linear Equation

Rationalize the denominator of \frac{2x}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.

$$y=\frac{2x\sqrt{3}}{\left(\sqrt{3}\right)^{2}}+n$$

The square of \sqrt{3} is 3.

$$y=\frac{2x\sqrt{3}}{3}+n$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{2x\sqrt{3}}{3}+n=y$$

Subtract n from both sides.

$$\frac{2x\sqrt{3}}{3}=y-n$$

Multiply both sides of the equation by 3.

$$2x\sqrt{3}=3y-3n$$

The equation is in standard form.

$$2\sqrt{3}x=3y-3n$$

Divide both sides by 2\sqrt{3}.

$$\frac{2\sqrt{3}x}{2\sqrt{3}}=\frac{3y-3n}{2\sqrt{3}}$$

Dividing by 2\sqrt{3} undoes the multiplication by 2\sqrt{3}.

$$x=\frac{3y-3n}{2\sqrt{3}}$$

Divide 3y-3n by 2\sqrt{3}.

$$x=\frac{\sqrt{3}\left(y-n\right)}{2}$$

Solve for n

$$n=-\frac{2\sqrt{3}x}{3}+y$$