Solve y=2/4x+3

$$y = \frac { 2 } { 4 x } + 3$$

Solve for x

$$x=-\frac{1}{2\left(3-y\right)}$$

$$y\neq 3$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 4x.

$$y\times 4x=2+4x\times 3$$

Multiply 4 and 3 to get 12.

$$y\times 4x=2+12x$$

Subtract 12x from both sides.

$$y\times 4x-12x=2$$

Combine all terms containing x.

$$\left(y\times 4-12\right)x=2$$

The equation is in standard form.

$$\left(4y-12\right)x=2$$

Divide both sides by 4y-12.

$$\frac{\left(4y-12\right)x}{4y-12}=\frac{2}{4y-12}$$

Dividing by 4y-12 undoes the multiplication by 4y-12.

$$x=\frac{2}{4y-12}$$

Divide 2 by 4y-12.

$$x=\frac{1}{2\left(y-3\right)}$$

Variable x cannot be equal to 0.

$$x=\frac{1}{2\left(y-3\right)}\text{, }x\neq 0$$

Solve for y

$$y=3+\frac{1}{2x}$$

$$x\neq 0$$