Solve y=2/3x+3

$$y = \frac { 2 } { 3 } x + 3$$

Solve for x

$$x=\frac{3\left(y-3\right)}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{2}{3}x+3=y$$

Subtract 3 from both sides.

$$\frac{2}{3}x=y-3$$

Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{3}x}{\frac{2}{3}}=\frac{y-3}{\frac{2}{3}}$$

Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.

$$x=\frac{y-3}{\frac{2}{3}}$$

Divide y-3 by \frac{2}{3} by multiplying y-3 by the reciprocal of \frac{2}{3}.

$$x=\frac{3y-9}{2}$$

Solve for y

$$y=\frac{2x}{3}+3$$