Solve for y
y=\frac{2\left(x-3\right)^{2}}{3}-5
Solve for x (complex solution)
x=-\frac{\sqrt{6y+30}}{2}+3
x=\frac{\sqrt{6y+30}}{2}+3
Solve for x
x=-\frac{\sqrt{6y+30}}{2}+3
x=\frac{\sqrt{6y+30}}{2}+3\text{, }y\geq -5
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y=\frac{2}{3}\left(x^{2}-6x+9\right)-5
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y=\frac{2}{3}x^{2}-4x+6-5
Use the distributive property to multiply \frac{2}{3} by x^{2}-6x+9.
y=\frac{2}{3}x^{2}-4x+1
Subtract 5 from 6 to get 1.
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