Solve y=1-3x/1+x

$$y = \frac { 1 - 3 x } { 1 + x }$$

Solve for x

$$x=-\frac{y-1}{y+3}$$

$$y\neq -3$$

Steps for Solving Linear Equation

Variable x cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by x+1.

$$y\left(x+1\right)=1-3x$$

Use the distributive property to multiply y by x+1.

$$yx+y=1-3x$$

Add 3x to both sides.

$$yx+y+3x=1$$

Subtract y from both sides.

$$yx+3x=1-y$$

Combine all terms containing x.

$$\left(y+3\right)x=1-y$$

Divide both sides by y+3.

$$\frac{\left(y+3\right)x}{y+3}=\frac{1-y}{y+3}$$

Dividing by y+3 undoes the multiplication by y+3.

$$x=\frac{1-y}{y+3}$$

Variable x cannot be equal to -1.

$$x=\frac{1-y}{y+3}\text{, }x\neq -1$$

Solve for y

$$y=-\frac{3x-1}{x+1}$$

$$x\neq -1$$