Solve y=1/x+3/1/3

$$y = \frac { 1 } { x } + \frac { 3 } { 1 / 3 }$$

Solve for x

$$x=-\frac{1}{9-y}$$

$$y\neq 9$$

Steps for Solving Linear Equation

Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.

$$yx=1+x\times \frac{3}{\frac{1}{3}}$$

Divide 3 by \frac{1}{3} by multiplying 3 by the reciprocal of \frac{1}{3}.

$$yx=1+x\times 3\times 3$$

Multiply 3 and 3 to get 9.

$$yx=1+x\times 9$$

Subtract x\times 9 from both sides.

$$yx-x\times 9=1$$

Multiply -1 and 9 to get -9.

$$yx-9x=1$$

Combine all terms containing x.

$$\left(y-9\right)x=1$$

Divide both sides by y-9.

$$\frac{\left(y-9\right)x}{y-9}=\frac{1}{y-9}$$

Dividing by y-9 undoes the multiplication by y-9.

$$x=\frac{1}{y-9}$$

Variable x cannot be equal to 0.

$$x=\frac{1}{y-9}\text{, }x\neq 0$$

Solve for y

$$y=9+\frac{1}{x}$$

$$x\neq 0$$