Solve y=1/x+3

$$y = \frac { 1 } { x + 3 }$$

Solve for x

$$x=-3+\frac{1}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.

$$y\left(x+3\right)=1$$

Use the distributive property to multiply y by x+3.

$$yx+3y=1$$

Subtract 3y from both sides.

$$yx=1-3y$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{1-3y}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{1-3y}{y}$$

Divide 1-3y by y.

$$x=-3+\frac{1}{y}$$

Variable x cannot be equal to -3.

$$x=-3+\frac{1}{y}\text{, }x\neq -3$$

Solve for y

$$y=\frac{1}{x+3}$$

$$x\neq -3$$