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y=\frac{1}{4}\left(x^{2}-6x+9\right)-1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y=\frac{1}{4}x^{2}-\frac{3}{2}x+\frac{9}{4}-1
Use the distributive property to multiply \frac{1}{4} by x^{2}-6x+9.
y=\frac{1}{4}x^{2}-\frac{3}{2}x+\frac{5}{4}
Subtract 1 from \frac{9}{4} to get \frac{5}{4}.