Solve y=1/3x^2-x^2+20y=

$$y = \frac { 1 } { 3 } x ^ { 2 } - x ^ { 2 } + 20 y =$$

Solve for y

$$y=\frac{2x^{2}}{57}$$

Steps for Solving Linear Equation

Combine \frac{1}{3}x^{2} and -x^{2} to get -\frac{2}{3}x^{2}.

$$y=-\frac{2}{3}x^{2}+20y$$

Subtract 20y from both sides.

$$y-20y=-\frac{2}{3}x^{2}$$

Combine y and -20y to get -19y.

$$-19y=-\frac{2}{3}x^{2}$$

The equation is in standard form.

$$-19y=-\frac{2x^{2}}{3}$$

Divide both sides by -19.

$$\frac{-19y}{-19}=-\frac{\frac{2x^{2}}{3}}{-19}$$

Dividing by -19 undoes the multiplication by -19.

$$y=-\frac{\frac{2x^{2}}{3}}{-19}$$

Divide -\frac{2x^{2}}{3} by -19.

$$y=\frac{2x^{2}}{57}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{114y}}{2}$$

$$x=\frac{\sqrt{114y}}{2}$$

Solve for x

$$x=\frac{\sqrt{114y}}{2}$$

$$x=-\frac{\sqrt{114y}}{2}\text{, }y\geq 0$$