Solve for y
y=\frac{\left(x-3\right)^{2}+18}{3}
Solve for x (complex solution)
x=-\sqrt{3y-18}+3
x=\sqrt{3y-18}+3
Solve for x
x=-\sqrt{3y-18}+3
x=\sqrt{3y-18}+3\text{, }y\geq 6
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y=\frac{1}{3}\left(x^{2}-6x+9\right)+6
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y=\frac{1}{3}x^{2}-2x+3+6
Use the distributive property to multiply \frac{1}{3} by x^{2}-6x+9.
y=\frac{1}{3}x^{2}-2x+9
Add 3 and 6 to get 9.
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