Solve for y
y=2\pi x^{2}+4x+15
Solve for x
x=\frac{\sqrt{2\left(\pi y+2-15\pi \right)}-2}{2\pi }
x=\frac{-\sqrt{2\left(\pi y+2-15\pi \right)}-2}{2\pi }\text{, }y\geq -\frac{2}{\pi }+15
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y=2\pi x^{2}+4x+15
Divide 1 by \frac{1}{2\pi x^{2}+4x+15} by multiplying 1 by the reciprocal of \frac{1}{2\pi x^{2}+4x+15}.
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