Solve y=-4x+40/3

$$y = \frac { - 4 x + 40 } { 3 }$$

Solve for x

$$x=-\frac{3y}{4}+10$$

Steps for Solving Linear Equation

Divide each term of -4x+40 by 3 to get -\frac{4}{3}x+\frac{40}{3}.

$$y=-\frac{4}{3}x+\frac{40}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{4}{3}x+\frac{40}{3}=y$$

Subtract \frac{40}{3} from both sides.

$$-\frac{4}{3}x=y-\frac{40}{3}$$

Divide both sides of the equation by -\frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{4}{3}x}{-\frac{4}{3}}=\frac{y-\frac{40}{3}}{-\frac{4}{3}}$$

Dividing by -\frac{4}{3} undoes the multiplication by -\frac{4}{3}.

$$x=\frac{y-\frac{40}{3}}{-\frac{4}{3}}$$

Divide y-\frac{40}{3} by -\frac{4}{3} by multiplying y-\frac{40}{3} by the reciprocal of -\frac{4}{3}.

$$x=-\frac{3y}{4}+10$$

Solve for y

$$y=\frac{40-4x}{3}$$

Solution Steps

Divide each term of -4x+40 by 3 to get -\frac{4}{3}x+\frac{40}{3}.

$$y=-\frac{4}{3}x+\frac{40}{3}$$