Solve y=-3/x+1-5

$$y = \frac { - 3 } { x + 1 } - 5$$

Solve for x

$$x=-\frac{y+8}{y+5}$$

$$y\neq -5$$

Steps for Solving Linear Equation

Variable x cannot be equal to -1 since division by zero is not defined. Multiply both sides of the equation by x+1.

$$y\left(x+1\right)=-3+\left(x+1\right)\left(-5\right)$$

Use the distributive property to multiply y by x+1.

$$yx+y=-3+\left(x+1\right)\left(-5\right)$$

Use the distributive property to multiply x+1 by -5.

$$yx+y=-3-5x-5$$

Subtract 5 from -3 to get -8.

$$yx+y=-8-5x$$

Add 5x to both sides.

$$yx+y+5x=-8$$

Subtract y from both sides.

$$yx+5x=-8-y$$

Combine all terms containing x.

$$\left(y+5\right)x=-8-y$$

The equation is in standard form.

$$\left(y+5\right)x=-y-8$$

Divide both sides by y+5.

$$\frac{\left(y+5\right)x}{y+5}=\frac{-y-8}{y+5}$$

Dividing by y+5 undoes the multiplication by y+5.

$$x=\frac{-y-8}{y+5}$$

Divide -8-y by y+5.

$$x=-\frac{y+8}{y+5}$$

Variable x cannot be equal to -1.

$$x=-\frac{y+8}{y+5}\text{, }x\neq -1$$

Solve for y

$$y=-\frac{5x+8}{x+1}$$

$$x\neq -1$$