Solve y=(x^2+0,2x)(x+1)/-1-x

$$y = \frac { ( x ^ { 2 } + 0,2 x ) ( x + 1 ) } { - 1 - x }$$

Solve for y

$$y=-x\left(x+0,2\right)$$

$$x\neq -1$$

Solution Steps

Extract the negative sign in x+1.

$$y=\frac{-\left(-x-1\right)\left(x^{2}+0,2x\right)}{-x-1}$$

Cancel out -x-1 in both numerator and denominator.

$$y=-\left(x^{2}+0,2x\right)$$

To find the opposite of x^{2}+0,2x, find the opposite of each term.

$$y=-x^{2}-0,2x$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{\sqrt{0,04-4y}}{2}-0,1\text{, }&y\neq -0,8\text{ and }y\leq \frac{1}{100}\\x=\frac{\sqrt{0,04-4y}}{2}-0,1\text{, }&y\leq \frac{1}{100}\end{matrix}\right.$$