Solve y=(-5)^2-4^2+(1/5)^0/3^-2+1?

$$y = \frac { ( - 5 ) ^ { 2 } - 4 ^ { 2 } + ( 1 / 5 ) ^ { 0 } } { 3 ^ { - 2 } + 1 } ?$$

Solve for y

$$y=9$$

Steps for Solving Linear Equation

Calculate -5 to the power of 2 and get 25.

$$y=\frac{25-4^{2}+\left(\frac{1}{5}\right)^{0}}{3^{-2}+1}$$

Calculate 4 to the power of 2 and get 16.

$$y=\frac{25-16+\left(\frac{1}{5}\right)^{0}}{3^{-2}+1}$$

Subtract 16 from 25 to get 9.

$$y=\frac{9+\left(\frac{1}{5}\right)^{0}}{3^{-2}+1}$$

Calculate \frac{1}{5} to the power of 0 and get 1.

$$y=\frac{9+1}{3^{-2}+1}$$

Add 9 and 1 to get 10.

$$y=\frac{10}{3^{-2}+1}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$y=\frac{10}{\frac{1}{9}+1}$$

Add \frac{1}{9} and 1 to get \frac{10}{9}.

$$y=\frac{10}{\frac{10}{9}}$$

Divide 10 by \frac{10}{9} by multiplying 10 by the reciprocal of \frac{10}{9}.

$$y=10\times \frac{9}{10}$$

Multiply 10 and \frac{9}{10} to get 9.

$$y=9$$

Assign y

$$y≔9$$