Solve y=(-3)^4-3^2+(-1/3)/2^0+4^1

$$y = \frac { ( - 3 ) ^ { 4 } - 3 ^ { 2 } + ( - \frac { 1 } { 3 } ) } { 2 ^ { 0 } + 4 ^ { 1 } }$$

Solve for y

$$y = \frac{43}{3} = 14\frac{1}{3} \approx 14.333333333$$

Steps for Solving Linear Equation

Calculate -3 to the power of 4 and get 81.

$$y=\frac{81-3^{2}-\frac{1}{3}}{2^{0}+4^{1}}$$

Calculate 3 to the power of 2 and get 9.

$$y=\frac{81-9-\frac{1}{3}}{2^{0}+4^{1}}$$

Subtract 9 from 81 to get 72.

$$y=\frac{72-\frac{1}{3}}{2^{0}+4^{1}}$$

Subtract \frac{1}{3} from 72 to get \frac{215}{3}.

$$y=\frac{\frac{215}{3}}{2^{0}+4^{1}}$$

Calculate 2 to the power of 0 and get 1.

$$y=\frac{\frac{215}{3}}{1+4^{1}}$$

Calculate 4 to the power of 1 and get 4.

$$y=\frac{\frac{215}{3}}{1+4}$$

Add 1 and 4 to get 5.

$$y=\frac{\frac{215}{3}}{5}$$

Express \frac{\frac{215}{3}}{5} as a single fraction.

$$y=\frac{215}{3\times 5}$$

Multiply 3 and 5 to get 15.

$$y=\frac{215}{15}$$

Reduce the fraction \frac{215}{15} to lowest terms by extracting and canceling out 5.

$$y=\frac{43}{3}$$

Assign y

$$y≔\frac{43}{3}$$