Solve y=frac{(-3)^{4}-3^2+(-1/3)^-3}{2^0+4^1}

$$y = \frac { ( - 3 ) ^ { 4 } - 3 ^ { 2 } + ( - \frac { 1 } { 3 } ) ^ { - 3 } } { 2 ^ { 0 } + 4 ^ { 1 } }$$

Solve for y

$$y=9$$

Steps for Solving Linear Equation

Calculate -3 to the power of 4 and get 81.

$$y=\frac{81-3^{2}+\left(-\frac{1}{3}\right)^{-3}}{2^{0}+4^{1}}$$

Calculate 3 to the power of 2 and get 9.

$$y=\frac{81-9+\left(-\frac{1}{3}\right)^{-3}}{2^{0}+4^{1}}$$

Subtract 9 from 81 to get 72.

$$y=\frac{72+\left(-\frac{1}{3}\right)^{-3}}{2^{0}+4^{1}}$$

Calculate -\frac{1}{3} to the power of -3 and get -27.

$$y=\frac{72-27}{2^{0}+4^{1}}$$

Subtract 27 from 72 to get 45.

$$y=\frac{45}{2^{0}+4^{1}}$$

Calculate 2 to the power of 0 and get 1.

$$y=\frac{45}{1+4^{1}}$$

Calculate 4 to the power of 1 and get 4.

$$y=\frac{45}{1+4}$$

Add 1 and 4 to get 5.

$$y=\frac{45}{5}$$

Divide 45 by 5 to get 9.

$$y=9$$

Assign y

$$y≔9$$