Solve y=(-3)^4-3^2+(-1/3)^-3/

$$y = \frac { ( - 3 ) ^ { 4 } - 3 ^ { 2 } + ( - \frac { 1 } { 3 } ) ^ { - 3 } } { }$$

Solve for y

$$y=45$$

Steps for Solving Linear Equation

Calculate -3 to the power of 4 and get 81.

$$y=\frac{81-3^{2}+\left(-\frac{1}{3}\right)^{-3}}{1}$$

Calculate 3 to the power of 2 and get 9.

$$y=\frac{81-9+\left(-\frac{1}{3}\right)^{-3}}{1}$$

Subtract 9 from 81 to get 72.

$$y=\frac{72+\left(-\frac{1}{3}\right)^{-3}}{1}$$

Calculate -\frac{1}{3} to the power of -3 and get -27.

$$y=\frac{72-27}{1}$$

Subtract 27 from 72 to get 45.

$$y=\frac{45}{1}$$

Anything divided by one gives itself.

$$y=45$$

Assign y

$$y≔45$$