Solve y=(-(x+1)/(-3,0)

$$y = \frac { ( - ( x + 1 ) } { ( - 3,0 ) }$$

Solve for x

$$x=3y-1$$

Steps for Solving Linear Equation

To find the opposite of x+1, find the opposite of each term.

$$y=\frac{-x-1}{-3}$$

Multiply both numerator and denominator by -1.

$$y=\frac{x+1}{3}$$

Divide each term of x+1 by 3 to get \frac{1}{3}x+\frac{1}{3}.

$$y=\frac{1}{3}x+\frac{1}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}x+\frac{1}{3}=y$$

Subtract \frac{1}{3} from both sides.

$$\frac{1}{3}x=y-\frac{1}{3}$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}x}{\frac{1}{3}}=\frac{y-\frac{1}{3}}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$x=\frac{y-\frac{1}{3}}{\frac{1}{3}}$$

Divide y-\frac{1}{3} by \frac{1}{3} by multiplying y-\frac{1}{3} by the reciprocal of \frac{1}{3}.

$$x=3y-1$$

Solve for y

$$y=\frac{x+1}{3}$$

Solution Steps

To find the opposite of x+1, find the opposite of each term.

$$y=\frac{-x-1}{-3}$$

Multiply both numerator and denominator by -1.

$$y=\frac{x+1}{3}$$

Divide each term of x+1 by 3 to get \frac{1}{3}x+\frac{1}{3}.

$$y=\frac{1}{3}x+\frac{1}{3}$$