Solve y=2/3*h^2-3/8r^3/A=

$$y = \frac { \frac { 2 } { 3 } \cdot h ^ { 2 } - \frac { 3 } { 8 } r ^ { 3 } } { A } =$$

Solve for A (complex solution)

$$\left\{\begin{matrix}A=-\frac{9r^{3}-16h^{2}}{24y}\text{, }&h\neq -\frac{3r^{\frac{3}{2}}}{4}\text{ and }h\neq \frac{3r^{\frac{3}{2}}}{4}\text{ and }y\neq 0\\A\neq 0\text{, }&\left(h=\frac{3r^{\frac{3}{2}}}{4}\text{ or }h=-\frac{3r^{\frac{3}{2}}}{4}\right)\text{ and }y=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable A cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by A.

$$yA=\frac{2}{3}h^{2}-\frac{3}{8}r^{3}$$

The equation is in standard form.

$$yA=-\frac{3r^{3}}{8}+\frac{2h^{2}}{3}$$

Divide both sides by y.

$$\frac{yA}{y}=\frac{-\frac{3r^{3}}{8}+\frac{2h^{2}}{3}}{y}$$

Dividing by y undoes the multiplication by y.

$$A=\frac{-\frac{3r^{3}}{8}+\frac{2h^{2}}{3}}{y}$$

Divide \frac{2h^{2}}{3}-\frac{3r^{3}}{8} by y.

$$A=\frac{16h^{2}-9r^{3}}{24y}$$

Variable A cannot be equal to 0.

$$A=\frac{16h^{2}-9r^{3}}{24y}\text{, }A\neq 0$$

Solve for A

$$\left\{\begin{matrix}A=-\frac{9r^{3}-16h^{2}}{24y}\text{, }&r\neq \frac{2\sqrt[3]{6}h^{\frac{2}{3}}}{3}\text{ and }y\neq 0\\A\neq 0\text{, }&y=0\text{ and }r=\frac{2\sqrt[3]{6}h^{\frac{2}{3}}}{3}\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable A cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by A.

$$yA=\frac{2}{3}h^{2}-\frac{3}{8}r^{3}$$

The equation is in standard form.

$$yA=-\frac{3r^{3}}{8}+\frac{2h^{2}}{3}$$

Divide both sides by y.

$$\frac{yA}{y}=\frac{-\frac{3r^{3}}{8}+\frac{2h^{2}}{3}}{y}$$

Dividing by y undoes the multiplication by y.

$$A=\frac{-\frac{3r^{3}}{8}+\frac{2h^{2}}{3}}{y}$$

Divide \frac{2h^{2}}{3}-\frac{3r^{3}}{8} by y.

$$A=\frac{16h^{2}-9r^{3}}{24y}$$

Variable A cannot be equal to 0.

$$A=\frac{16h^{2}-9r^{3}}{24y}\text{, }A\neq 0$$

Solve for h (complex solution)

$$h=-\frac{\sqrt{24Ay+9r^{3}}}{4}$$

$$h=\frac{\sqrt{24Ay+9r^{3}}}{4}\text{, }A\neq 0$$

Solve for h

$$h=\frac{\sqrt{24Ay+9r^{3}}}{4}$$

$$h=-\frac{\sqrt{24Ay+9r^{3}}}{4}\text{, }A\neq 0\text{ and }r\geq -\frac{2\times 3^{\frac{2}{3}}\sqrt[3]{Ay}}{3}$$