Solve y=2sqrt{x+1}

$$y = 2 \sqrt{ x+1 }$$

Solve for x

$$x=\frac{y^{2}-4}{4}$$

$$y\geq 0$$

Steps for Solving Radical Equations

Swap sides so that all variable terms are on the left hand side.

$$2\sqrt{x+1}=y$$

Divide both sides by 2.

$$\frac{2\sqrt{x+1}}{2}=\frac{y}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$\sqrt{x+1}=\frac{y}{2}$$

Square both sides of the equation.

$$x+1=\frac{y^{2}}{4}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{y^{2}}{4}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{y^{2}}{4}-1$$

Solve for x (complex solution)

$$x=\frac{y^{2}-4}{4}$$

$$arg(y)<\pi \text{ or }y=0$$

Solve for y

$$y=2\sqrt{x+1}$$

$$x\geq -1$$