Solve for x
x=-\frac{2y}{3}-2
Solve for y
y=-\frac{3x}{2}-3
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-\frac{3}{2}x-3=y
Swap sides so that all variable terms are on the left hand side.
-\frac{3}{2}x=y+3
Add 3 to both sides.
\frac{-\frac{3}{2}x}{-\frac{3}{2}}=\frac{y+3}{-\frac{3}{2}}
Divide both sides of the equation by -\frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{y+3}{-\frac{3}{2}}
Dividing by -\frac{3}{2} undoes the multiplication by -\frac{3}{2}.
x=-\frac{2y}{3}-2
Divide y+3 by -\frac{3}{2} by multiplying y+3 by the reciprocal of -\frac{3}{2}.
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