Solve y=-2/3x+2z

$$y = - \frac{ 2 }{ 3 } x+2z$$

Solve for x

$$x=-\frac{3y}{2}+3z$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}x+2z=y$$

Subtract 2z from both sides.

$$-\frac{2}{3}x=y-2z$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y-2z}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y-2z}{-\frac{2}{3}}$$

Divide y-2z by -\frac{2}{3} by multiplying y-2z by the reciprocal of -\frac{2}{3}.

$$x=-\frac{3y}{2}+3z$$

Solve for y

$$y=-\frac{2x}{3}+2z$$