Solve y=-1/63^2+5/6(3)+4

$$y = - \frac{ 1 }{ 6 } { 3 }^{ 2 } + \frac{ 5 }{ 6 } (3)+4$$

Solve for y

$$y=5$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$y=-\frac{1}{6}\times 9+\frac{5}{6}\times 3+4$$

Express -\frac{1}{6}\times 9 as a single fraction.

$$y=\frac{-9}{6}+\frac{5}{6}\times 3+4$$

Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.

$$y=-\frac{3}{2}+\frac{5}{6}\times 3+4$$

Express \frac{5}{6}\times 3 as a single fraction.

$$y=-\frac{3}{2}+\frac{5\times 3}{6}+4$$

Multiply 5 and 3 to get 15.

$$y=-\frac{3}{2}+\frac{15}{6}+4$$

Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.

$$y=-\frac{3}{2}+\frac{5}{2}+4$$

Since -\frac{3}{2} and \frac{5}{2} have the same denominator, add them by adding their numerators.

$$y=\frac{-3+5}{2}+4$$

Add -3 and 5 to get 2.

$$y=\frac{2}{2}+4$$

Divide 2 by 2 to get 1.

$$y=1+4$$

Add 1 and 4 to get 5.

$$y=5$$

Assign y

$$y≔5$$