Solve for x
x=y^{2}+4
y\geq 0
Solve for x (complex solution)
x=y^{2}+4
arg(y)<\pi \text{ or }y=0
Solve for y
y=\sqrt{x-4}
x\geq 4
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\sqrt{x-4}=y
Swap sides so that all variable terms are on the left hand side.
x-4=y^{2}
Square both sides of the equation.
x-4-\left(-4\right)=y^{2}-\left(-4\right)
Add 4 to both sides of the equation.
x=y^{2}-\left(-4\right)
Subtracting -4 from itself leaves 0.
x=y^{2}+4
Subtract -4 from y^{2}.
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