Solve for y
y=\frac{\left(x-3\right)^{2}}{2}
Solve for x (complex solution)
x=-\sqrt{2y}+3
x=\sqrt{2y}+3
Solve for x
x=-\sqrt{2y}+3
x=\sqrt{2y}+3\text{, }y\geq 0
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y=\frac{1}{2}\left(x^{2}-6x+9\right)\times 1
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y=\frac{1}{2}\left(x^{2}-6x+9\right)
Multiply \frac{1}{2} and 1 to get \frac{1}{2}.
y=\frac{1}{2}x^{2}-3x+\frac{9}{2}
Use the distributive property to multiply \frac{1}{2} by x^{2}-6x+9.
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