Solve y=1/x^-4

$$y = \frac{ 1 }{ { x }^{ } -4 }$$

Solve for x

$$x=4+\frac{1}{y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Variable x cannot be equal to 4 since division by zero is not defined. Multiply both sides of the equation by x-4.

$$y\left(x-4\right)=1$$

Use the distributive property to multiply y by x-4.

$$yx-4y=1$$

Add 4y to both sides.

$$yx=1+4y$$

The equation is in standard form.

$$yx=4y+1$$

Divide both sides by y.

$$\frac{yx}{y}=\frac{4y+1}{y}$$

Dividing by y undoes the multiplication by y.

$$x=\frac{4y+1}{y}$$

Divide 1+4y by y.

$$x=4+\frac{1}{y}$$

Variable x cannot be equal to 4.

$$x=4+\frac{1}{y}\text{, }x\neq 4$$

Solve for y

$$y=\frac{1}{x-4}$$

$$x\neq 4$$