Solve y=-5^2-4^2+(1^/5)0/3^-2+1

$$y = \frac{ { -5 }^{ 2 } - { 4 }^{ 2 } +( \frac{ { 1 }^{ } }{ 5 } )0 }{ { 3 }^{ -2 } +1 }$$

Solve for y

$$y = \frac{81}{10} = 8\frac{1}{10} = 8.1$$

Steps for Solving Linear Equation

Calculate -5 to the power of 2 and get 25.

$$y=\frac{25-4^{2}+\frac{1^{1}}{5}\times 0}{3^{-2}+1}$$

Calculate 4 to the power of 2 and get 16.

$$y=\frac{25-16+\frac{1^{1}}{5}\times 0}{3^{-2}+1}$$

Subtract 16 from 25 to get 9.

$$y=\frac{9+\frac{1^{1}}{5}\times 0}{3^{-2}+1}$$

Calculate 1 to the power of 1 and get 1.

$$y=\frac{9+\frac{1}{5}\times 0}{3^{-2}+1}$$

Multiply \frac{1}{5} and 0 to get 0.

$$y=\frac{9+0}{3^{-2}+1}$$

Add 9 and 0 to get 9.

$$y=\frac{9}{3^{-2}+1}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$y=\frac{9}{\frac{1}{9}+1}$$

Add \frac{1}{9} and 1 to get \frac{10}{9}.

$$y=\frac{9}{\frac{10}{9}}$$

Divide 9 by \frac{10}{9} by multiplying 9 by the reciprocal of \frac{10}{9}.

$$y=9\times \frac{9}{10}$$

Multiply 9 and \frac{9}{10} to get \frac{81}{10}.

$$y=\frac{81}{10}$$

Assign y

$$y≔\frac{81}{10}$$