Solve for y
y=x^{2}+x+1
Solve for x (complex solution)
x=\frac{-\sqrt{4y-3}-1}{2}
x=\frac{\sqrt{4y-3}-1}{2}
Solve for x
x=\frac{-\sqrt{4y-3}-1}{2}
x=\frac{\sqrt{4y-3}-1}{2}\text{, }y\geq \frac{3}{4}
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y=\frac{x^{2}-2x+1+3x}{1}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
y=\frac{x^{2}+x+1}{1}
Combine -2x and 3x to get x.
y=x^{2}+x+1
Anything divided by one gives itself.
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