Solve y+6=-2/3x+1

$$y + 6 = - \frac { 2 } { 3 } x + 1$$

Solve for x

$$x=\frac{-3y-15}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}x+1=y+6$$

Subtract 1 from both sides.

$$-\frac{2}{3}x=y+6-1$$

Subtract 1 from 6 to get 5.

$$-\frac{2}{3}x=y+5$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y+5}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y+5}{-\frac{2}{3}}$$

Divide y+5 by -\frac{2}{3} by multiplying y+5 by the reciprocal of -\frac{2}{3}.

$$x=\frac{-3y-15}{2}$$

Solve for y

$$y=-\frac{2x}{3}-5$$

Solution Steps

Subtract 6 from both sides.

$$y=-\frac{2}{3}x+1-6$$

Subtract 6 from 1 to get -5.

$$y=-\frac{2}{3}x-5$$