Solve y+3=7/8(x-4)

$$y + 3 = \frac { 7 } { 8 } ( x - 4 )$$

Solve for x

$$x=\frac{8y+52}{7}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{7}{8} by x-4.

$$y+3=\frac{7}{8}x-\frac{7}{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{7}{8}x-\frac{7}{2}=y+3$$

Add \frac{7}{2} to both sides.

$$\frac{7}{8}x=y+3+\frac{7}{2}$$

Add 3 and \frac{7}{2} to get \frac{13}{2}.

$$\frac{7}{8}x=y+\frac{13}{2}$$

Divide both sides of the equation by \frac{7}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{8}x}{\frac{7}{8}}=\frac{y+\frac{13}{2}}{\frac{7}{8}}$$

Dividing by \frac{7}{8} undoes the multiplication by \frac{7}{8}.

$$x=\frac{y+\frac{13}{2}}{\frac{7}{8}}$$

Divide y+\frac{13}{2} by \frac{7}{8} by multiplying y+\frac{13}{2} by the reciprocal of \frac{7}{8}.

$$x=\frac{8y+52}{7}$$

Solve for y

$$y=\frac{7x}{8}-\frac{13}{2}$$

Solution Steps

Use the distributive property to multiply \frac{7}{8} by x-4.

$$y+3=\frac{7}{8}x-\frac{7}{2}$$

Subtract 3 from both sides.

$$y=\frac{7}{8}x-\frac{7}{2}-3$$

Subtract 3 from -\frac{7}{2} to get -\frac{13}{2}.

$$y=\frac{7}{8}x-\frac{13}{2}$$