Solve for y
y=-\frac{\left(3-x\right)\left(x-9\right)}{3}
Solve for x (complex solution)
x=-\sqrt{3\left(y+3\right)}+6
x=\sqrt{3\left(y+3\right)}+6
Solve for x
x=-\sqrt{3\left(y+3\right)}+6
x=\sqrt{3\left(y+3\right)}+6\text{, }y\geq -3
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y+3=\frac{1}{3}\left(x^{2}-12x+36\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-6\right)^{2}.
y+3=\frac{1}{3}x^{2}-4x+12
Use the distributive property to multiply \frac{1}{3} by x^{2}-12x+36.
y=\frac{1}{3}x^{2}-4x+12-3
Subtract 3 from both sides.
y=\frac{1}{3}x^{2}-4x+9
Subtract 3 from 12 to get 9.
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