Solve y+2=5/3(x-3)quad

$$y + 2 = \frac { 5 } { 3 } ( x - 3 ) \quad$$

Solve for x

$$x=\frac{3\left(y+7\right)}{5}$$

Steps for Solving Linear Equation

Use the distributive property to multiply \frac{5}{3} by x-3.

$$y+2=\frac{5}{3}x-5$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{5}{3}x-5=y+2$$

Add 5 to both sides.

$$\frac{5}{3}x=y+2+5$$

Add 2 and 5 to get 7.

$$\frac{5}{3}x=y+7$$

Divide both sides of the equation by \frac{5}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{3}x}{\frac{5}{3}}=\frac{y+7}{\frac{5}{3}}$$

Dividing by \frac{5}{3} undoes the multiplication by \frac{5}{3}.

$$x=\frac{y+7}{\frac{5}{3}}$$

Divide y+7 by \frac{5}{3} by multiplying y+7 by the reciprocal of \frac{5}{3}.

$$x=\frac{3y+21}{5}$$

Solve for y

$$y=\frac{5x}{3}-7$$

Solution Steps

Use the distributive property to multiply \frac{5}{3} by x-3.

$$y+2=\frac{5}{3}x-5$$

Subtract 2 from both sides.

$$y=\frac{5}{3}x-5-2$$

Subtract 2 from -5 to get -7.

$$y=\frac{5}{3}x-7$$