Solve y+1=-2quad(x-3)

$$y + 1 = - 2 \quad ( x - 3 )$$

Solve for x

$$x=\frac{5-y}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -2 by x-3.

$$y+1=-2x+6$$

Swap sides so that all variable terms are on the left hand side.

$$-2x+6=y+1$$

Subtract 6 from both sides.

$$-2x=y+1-6$$

Subtract 6 from 1 to get -5.

$$-2x=y-5$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{y-5}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{y-5}{-2}$$

Divide y-5 by -2.

$$x=\frac{5-y}{2}$$

Solve for y

$$y=5-2x$$

Solution Steps

Use the distributive property to multiply -2 by x-3.

$$y+1=-2x+6$$

Subtract 1 from both sides.

$$y=-2x+6-1$$

Subtract 1 from 6 to get 5.

$$y=-2x+5$$