Solve y+1=-4/3(x-5)

$$y + 1 = - \frac { 4 } { 3 } ( x - 5 )$$

Solve for x

$$x=\frac{17-3y}{4}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{4}{3} by x-5.

$$y+1=-\frac{4}{3}x+\frac{20}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{4}{3}x+\frac{20}{3}=y+1$$

Subtract \frac{20}{3} from both sides.

$$-\frac{4}{3}x=y+1-\frac{20}{3}$$

Subtract \frac{20}{3} from 1 to get -\frac{17}{3}.

$$-\frac{4}{3}x=y-\frac{17}{3}$$

Divide both sides of the equation by -\frac{4}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{4}{3}x}{-\frac{4}{3}}=\frac{y-\frac{17}{3}}{-\frac{4}{3}}$$

Dividing by -\frac{4}{3} undoes the multiplication by -\frac{4}{3}.

$$x=\frac{y-\frac{17}{3}}{-\frac{4}{3}}$$

Divide y-\frac{17}{3} by -\frac{4}{3} by multiplying y-\frac{17}{3} by the reciprocal of -\frac{4}{3}.

$$x=\frac{17-3y}{4}$$

Solve for y

$$y=\frac{17-4x}{3}$$

Solution Steps

Use the distributive property to multiply -\frac{4}{3} by x-5.

$$y+1=-\frac{4}{3}x+\frac{20}{3}$$

Subtract 1 from both sides.

$$y=-\frac{4}{3}x+\frac{20}{3}-1$$

Subtract 1 from \frac{20}{3} to get \frac{17}{3}.

$$y=-\frac{4}{3}x+\frac{17}{3}$$