Solve y+1=-2/3(x+2)

$$y + 1 = - \frac { 2 } { 3 } ( x + 2 )$$

Solve for x

$$x=\frac{-3y-7}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply -\frac{2}{3} by x+2.

$$y+1=-\frac{2}{3}x-\frac{4}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{2}{3}x-\frac{4}{3}=y+1$$

Add \frac{4}{3} to both sides.

$$-\frac{2}{3}x=y+1+\frac{4}{3}$$

Add 1 and \frac{4}{3} to get \frac{7}{3}.

$$-\frac{2}{3}x=y+\frac{7}{3}$$

Divide both sides of the equation by -\frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{2}{3}x}{-\frac{2}{3}}=\frac{y+\frac{7}{3}}{-\frac{2}{3}}$$

Dividing by -\frac{2}{3} undoes the multiplication by -\frac{2}{3}.

$$x=\frac{y+\frac{7}{3}}{-\frac{2}{3}}$$

Divide y+\frac{7}{3} by -\frac{2}{3} by multiplying y+\frac{7}{3} by the reciprocal of -\frac{2}{3}.

$$x=\frac{-3y-7}{2}$$

Solve for y

$$y=\frac{-2x-7}{3}$$

Solution Steps

Use the distributive property to multiply -\frac{2}{3} by x+2.

$$y+1=-\frac{2}{3}x-\frac{4}{3}$$

Subtract 1 from both sides.

$$y=-\frac{2}{3}x-\frac{4}{3}-1$$

Subtract 1 from -\frac{4}{3} to get -\frac{7}{3}.

$$y=-\frac{2}{3}x-\frac{7}{3}$$