Solve y+7/3z=7/3

$$y + \frac { 7 } { 3 } z = \frac { 7 } { 3 }$$

Solve for z

$$z=-\frac{3y}{7}+1$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$\frac{7}{3}z=\frac{7}{3}-y$$

Divide both sides of the equation by \frac{7}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{7}{3}z}{\frac{7}{3}}=\frac{\frac{7}{3}-y}{\frac{7}{3}}$$

Dividing by \frac{7}{3} undoes the multiplication by \frac{7}{3}.

$$z=\frac{\frac{7}{3}-y}{\frac{7}{3}}$$

Divide \frac{7}{3}-y by \frac{7}{3} by multiplying \frac{7}{3}-y by the reciprocal of \frac{7}{3}.

$$z=-\frac{3y}{7}+1$$

Solve for y

$$y=\frac{7-7z}{3}$$

Solution Steps

Subtract \frac{7}{3}z from both sides.

$$y=\frac{7}{3}-\frac{7}{3}z$$