Solve y+3/4geq1/5

$$y + \frac { 3 } { 4 } \geq \frac { 1 } { 5 }$$

Solve for y

$$y\geq -\frac{11}{20}$$

Solution Steps

Subtract \frac{3}{4} from both sides.

$$y\geq \frac{1}{5}-\frac{3}{4}$$

Least common multiple of 5 and 4 is 20. Convert \frac{1}{5} and \frac{3}{4} to fractions with denominator 20.

$$y\geq \frac{4}{20}-\frac{15}{20}$$

Since \frac{4}{20} and \frac{15}{20} have the same denominator, subtract them by subtracting their numerators.

$$y\geq \frac{4-15}{20}$$

Subtract 15 from 4 to get -11.

$$y\geq -\frac{11}{20}$$