Solve for x
x=-\frac{2y-1}{y-3}
y\neq 3
Solve for y
y=\frac{3x+1}{x+2}
x\neq -2
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xy-3x=1-2y
Subtract 2y from both sides.
\left(y-3\right)x=1-2y
Combine all terms containing x.
\frac{\left(y-3\right)x}{y-3}=\frac{1-2y}{y-3}
Divide both sides by y-3.
x=\frac{1-2y}{y-3}
Dividing by y-3 undoes the multiplication by y-3.
xy+2y=1+3x
Add 3x to both sides.
\left(x+2\right)y=1+3x
Combine all terms containing y.
\left(x+2\right)y=3x+1
The equation is in standard form.
\frac{\left(x+2\right)y}{x+2}=\frac{3x+1}{x+2}
Divide both sides by x+2.
y=\frac{3x+1}{x+2}
Dividing by x+2 undoes the multiplication by x+2.
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