Solve x4-13x^2+36=0

$$x4-13 { x }^{ 2 } +36=0$$

Solve for x_4

$$x_{4}=13x^{2}-36$$

Solution Steps

Add 13x^{2} to both sides. Anything plus zero gives itself.

$$x_{4}+36=13x^{2}$$

Subtract 36 from both sides.

$$x_{4}=13x^{2}-36$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{13\left(x_{4}+36\right)}}{13}$$

$$x=\frac{\sqrt{13\left(x_{4}+36\right)}}{13}$$

Solve for x

$$x=\frac{\sqrt{13\left(x_{4}+36\right)}}{13}$$

$$x=-\frac{\sqrt{13\left(x_{4}+36\right)}}{13}\text{, }x_{4}\geq -36$$