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Solve for x_4
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3x-1=x_{4}+6
Swap sides so that all variable terms are on the left hand side.
3x=x_{4}+6+1
Add 1 to both sides.
3x=x_{4}+7
Add 6 and 1 to get 7.
\frac{3x}{3}=\frac{x_{4}+7}{3}
Divide both sides by 3.
x=\frac{x_{4}+7}{3}
Dividing by 3 undoes the multiplication by 3.
x_{4}=3x-1-6
Subtract 6 from both sides.
x_{4}=3x-7
Subtract 6 from -1 to get -7.