Solve x2-4x2+9x-36=0

$$x2-4x2+9x-36=0$$

Solve for x

$$x=\frac{x_{2}+12}{3}$$

Steps for Solving Linear Equation

Combine x_{2} and -4x_{2} to get -3x_{2}.

$$-3x_{2}+9x-36=0$$

Add 3x_{2} to both sides. Anything plus zero gives itself.

$$9x-36=3x_{2}$$

Add 36 to both sides.

$$9x=3x_{2}+36$$

Divide both sides by 9.

$$\frac{9x}{9}=\frac{3x_{2}+36}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x=\frac{3x_{2}+36}{9}$$

Divide 36+3x_{2} by 9.

$$x=\frac{x_{2}}{3}+4$$

Solve for x_2

$$x_{2}=3\left(x-4\right)$$

Steps for Solving Linear Equation

Combine x_{2} and -4x_{2} to get -3x_{2}.

$$-3x_{2}+9x-36=0$$

Subtract 9x from both sides. Anything subtracted from zero gives its negation.

$$-3x_{2}-36=-9x$$

Add 36 to both sides.

$$-3x_{2}=-9x+36$$

The equation is in standard form.

$$-3x_{2}=36-9x$$

Divide both sides by -3.

$$\frac{-3x_{2}}{-3}=\frac{36-9x}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x_{2}=\frac{36-9x}{-3}$$

Divide -9x+36 by -3.

$$x_{2}=3x-12$$