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Solve for x_2
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-3x-10=-x_{2}
Subtract x_{2} from both sides. Anything subtracted from zero gives its negation.
-3x=-x_{2}+10
Add 10 to both sides.
-3x=10-x_{2}
The equation is in standard form.
\frac{-3x}{-3}=\frac{10-x_{2}}{-3}
Divide both sides by -3.
x=\frac{10-x_{2}}{-3}
Dividing by -3 undoes the multiplication by -3.
x=\frac{x_{2}-10}{3}
Divide -x_{2}+10 by -3.
x_{2}-10=3x
Add 3x to both sides. Anything plus zero gives itself.
x_{2}=3x+10
Add 10 to both sides.