Solve x2+8-y=y

$$x2+8-y=y$$

Solve for x_2

$$x_{2}=2\left(y-4\right)$$

Solution Steps

Subtract 8 from both sides.

$$x_{2}-y=y-8$$

Add y to both sides.

$$x_{2}=y-8+y$$

Combine y and y to get 2y.

$$x_{2}=2y-8$$

Solve for y

$$y=\frac{x_{2}+8}{2}$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$x_{2}+8-y-y=0$$

Combine -y and -y to get -2y.

$$x_{2}+8-2y=0$$

Subtract x_{2} from both sides. Anything subtracted from zero gives its negation.

$$8-2y=-x_{2}$$

Subtract 8 from both sides.

$$-2y=-x_{2}-8$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{-x_{2}-8}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{-x_{2}-8}{-2}$$

Divide -x_{2}-8 by -2.

$$y=\frac{x_{2}}{2}+4$$